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I am trying to manipulate a file which contains numbers in scientific notation, but without the e symbol, i.e. 1.2e+3 is written as 1.2+3.

The easiest thing I thought to doing with awk was to replace + with e+, using the gsub function and do my calculation in the new file. The same goes for the minus case. So a simple fix could be done using the following command

awk '{gsub("+", "e+", $1); print $1, $2, $3, $4, $5}' file_in

and do the same in all the columns.

However the file contains also negative numbers which makes thing a bit complicated. A sample file can be seen bellow

 1.056000+0 5.000000-1 2.454400-3 2.914800-2 8.141500-6

 2.043430+1 5.000000-1 2.750500-3 2.698100-2-2.034300-4

 3.829842+1 5.000000-1 1.969923-2 2.211364-2 9.499900-6

 4.168521+1 5.000000-1 1.601262-2 3.030919-2-3.372000-6

 6.661784+1 5.000000-1 5.250575-2 3.443669-2 2.585500-5

 7.278104+1 5.000000-1 2.137055-2 2.601701-2 8.999800-5

 9.077287+1 5.000000-1 1.320498-2 2.961020-2-1.011600-5

 9.248130+1 5.000000-1 3.069610-3 2.786329-2-6.317000-5

 1.049935+2 5.000000-1 4.218794-2 3.321955-2-5.097000-6

 1.216283+2 5.000000-1 1.432105-2 3.077165-2 4.300300-5

Any idea on how to manipulate and calculations with such a file?

Is this output correct?

 1.056000e+0 5.000000e-1 2.454400e-3 2.914800e-2 8.141500e-6

 2.043430e+1 5.000000e-1 2.750500e-3 2.698100e-2-2.034300e-4

 3.829842e+1 5.000000e-1 1.969923e-2 2.211364e-2 9.499900e-6

 4.168521e+1 5.000000e-1 1.601262e-2 3.030919e-2-3.372000e-6

 6.661784e+1 5.000000e-1 5.250575e-2 3.443669e-2 2.585500e-5

 7.278104e+1 5.000000e-1 2.137055e-2 2.601701e-2 8.999800e-5

 9.077287e+1 5.000000e-1 1.320498e-2 2.961020e-2-1.011600e-5

 9.248130e+1 5.000000e-1 3.069610e-3 2.786329e-2-6.317000e-5

 1.049935e+2 5.000000e-1 4.218794e-2 3.321955e-2-5.097000e-6

 1.216283e+2 5.000000e-1 1.432105e-2 3.077165e-2 4.300300e-5

Code:

perl -lne 's/(.d+)(+|-)/1e2/g; print' sample

Explanation:

• -lne take care of line endings, process each input line, execute the code that follows



• 
  

  s/(.d+)(+|-)/1e2/g:

  
  
  
  
  
  • substitute (s)
  
  
  • 
    (.d+)(+|-) find two groups of (a dot and numbers) and (a plus or minus)
  
  
  • 
    1e2 substitute them with the first group then e then the second group
  
  
  • 
    g globally - don't stop at the first substitution in each line, but process all possible hits
  
  
  
  



• print print the line



• 
  sample input file

This one adds space if it's missing. In fact it puts space between the numbers regardless. Ie. if there were two spaces in some case, there would be only one in the output.

perl -lne 's/(.d+)(+|-)(d+)(s*)/1e23 /g; print' sample

Most of it is similar to the previous one. The new thing is the (d+) group nr 3 and the (s*) group nr 4. * here means optional. In the substitution no 4 is used. There's a space instead.

The output is this:

 1.056000e+0 5.000000e-1 2.454400e-3 2.914800e-2 8.141500e-6 

 2.043430e+1 5.000000e-1 2.750500e-3 2.698100e-2 -2.034300e-4 

 3.829842e+1 5.000000e-1 1.969923e-2 2.211364e-2 9.499900e-6 

 4.168521e+1 5.000000e-1 1.601262e-2 3.030919e-2 -3.372000e-6 

 6.661784e+1 5.000000e-1 5.250575e-2 3.443669e-2 2.585500e-5 

 7.278104e+1 5.000000e-1 2.137055e-2 2.601701e-2 8.999800e-5 

 9.077287e+1 5.000000e-1 1.320498e-2 2.961020e-2 -1.011600e-5 

 9.248130e+1 5.000000e-1 3.069610e-3 2.786329e-2 -6.317000e-5 

 1.049935e+2 5.000000e-1 4.218794e-2 3.321955e-2 -5.097000e-6 

 1.216283e+2 5.000000e-1 1.432105e-2 3.077165e-2 4.300300e-5 

You could also use sed, e.g.:

<infile sed -E 's/([0-9])([+-])([0-9])/1e23/g' | awk '{ print $1 + 0 }'

Output:

1.056

20.4343

38.2984

41.6852

66.6178

72.781

90.7729

92.4813

104.993

121.628