Ryfujk

What is Cash Advance APR?

putting logo on same line but after title, latex

Using substitution ciphers to generate new alphabets in a novel

Lowest total scrabble score

What is the highest possible scrabble score for placing a single tile

15% tax on $7.5k earnings. Is that right?

How can "mimic phobia" be cured or prevented?

How to hide some fields of struct in C?

Store Credit Card Information in Password Manager?

Are Captain Marvel's powers affected by Thanos' actions in Infinity War

What if a revenant (monster) gains fire resistance?

Why should universal income be universal?

Why is so much work done on numerical verification of the Riemann Hypothesis?

Is aluminum electrical wire used on aircraft?

What are some good ways to treat frozen vegetables such that they behave like fresh vegetables when stir frying them?

Multiplicative persistence

Need help understanding what a natural log transformation is actually doing and why specific transformations are required for linear regression

Can a College of Swords bard use a Blade Flourish option on an opportunity attack provoked by their own Dissonant Whispers spell?

Why is the "ls" command showing permissions of files in a FAT32 partition?

What happens if you are holding an Iron Flask with a demon inside and walk into an Antimagic Field?

Creepy dinosaur pc game identification

How much character growth crosses the line into breaking the character

How could a planet have erratic days?

Unexpected behavior of the procedure `Area` on the object 'Polygon'

How to fade a semiplane defined by line?

How can I stop defined points that are not displayed from influencing image size?LaTeX complains that tkzDrawArc is not definedHow to draw a dashed line and length with tkz-euclideColor fade a line in tikzpictureHow may I extend (prolong or produce) a line segment accurately in the following geometrical figure?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingDraw Perpendicular to a lineHow to fade the color of an angle?Fade draw and fill in TikZHow to use points defined in tkz-euclide in tikz?

3

With the following code:

documentclass[tikz]{standalone}



usepackage{tkz-euclide,tkz-fct,amsmath}

usetkzobj{all}





begin{document}

    begin{tikzpicture}[anchor=center]

        tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]

        tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}



        tkzDrawX[noticks, label={(operatorname{Re}(x) )}]

        tkzDrawY[noticks, label={(operatorname{Im}(x) )}]



        tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)

        tkzMarkRightAngle(A,M,P_1)

        tkzFct[domain=-1:3, color=red, thick]{x-.5}

        draw (P_1) -- (P_2);

        tkzLabelPoints[above right](P_1,P_2)

        tkzLabelPoints[right](M)



        tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}

    end{tikzpicture}

end{document}

I'm getting:

I wanted to add a fade like this:

but I can't have the fade to be in the right angle.

How can I get this kind of fade, fadding to white?

tikz-pgf tkz-euclide

share|improve this question

asked 5 hours ago

Concept7Concept7

916

add a comment | 

3

With the following code:

documentclass[tikz]{standalone}



usepackage{tkz-euclide,tkz-fct,amsmath}

usetkzobj{all}





begin{document}

    begin{tikzpicture}[anchor=center]

        tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]

        tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}



        tkzDrawX[noticks, label={(operatorname{Re}(x) )}]

        tkzDrawY[noticks, label={(operatorname{Im}(x) )}]



        tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)

        tkzMarkRightAngle(A,M,P_1)

        tkzFct[domain=-1:3, color=red, thick]{x-.5}

        draw (P_1) -- (P_2);

        tkzLabelPoints[above right](P_1,P_2)

        tkzLabelPoints[right](M)



        tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}

    end{tikzpicture}

end{document}

I'm getting:

I wanted to add a fade like this:

but I can't have the fade to be in the right angle.

How can I get this kind of fade, fadding to white?

tikz-pgf tkz-euclide

share|improve this question

asked 5 hours ago

Concept7Concept7

916

add a comment | 

With the following code:

documentclass[tikz]{standalone}



usepackage{tkz-euclide,tkz-fct,amsmath}

usetkzobj{all}





begin{document}

    begin{tikzpicture}[anchor=center]

        tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]

        tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}



        tkzDrawX[noticks, label={(operatorname{Re}(x) )}]

        tkzDrawY[noticks, label={(operatorname{Im}(x) )}]



        tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)

        tkzMarkRightAngle(A,M,P_1)

        tkzFct[domain=-1:3, color=red, thick]{x-.5}

        draw (P_1) -- (P_2);

        tkzLabelPoints[above right](P_1,P_2)

        tkzLabelPoints[right](M)



        tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}

    end{tikzpicture}

end{document}

I'm getting:

I wanted to add a fade like this:

but I can't have the fade to be in the right angle.

How can I get this kind of fade, fadding to white?

tikz-pgf tkz-euclide

share|improve this question

asked 5 hours ago

Concept7Concept7

916

documentclass[tikz]{standalone}



usepackage{tkz-euclide,tkz-fct,amsmath}

usetkzobj{all}





begin{document}

    begin{tikzpicture}[anchor=center]

        tkzInit[xmin=-1, xmax=3, ymin=-1,ymax=3]

        tkzDefPoints{.5/2/P_1, 2.5/0/P_2, 1.5/1/M,2/1.5/A}



        tkzDrawX[noticks, label={(operatorname{Re}(x) )}]

        tkzDrawY[noticks, label={(operatorname{Im}(x) )}]



        tkzDrawPoints[fill=black, size=1mm](P_1,P_2,M)

        tkzMarkRightAngle(A,M,P_1)

        tkzFct[domain=-1:3, color=red, thick]{x-.5}

        draw (P_1) -- (P_2);

        tkzLabelPoints[above right](P_1,P_2)

        tkzLabelPoints[right](M)



        tkzText[color=black](1.5,3){(|z-z_1|leq|z-z_2| )}

    end{tikzpicture}

end{document}

share|improve this question

asked 5 hours ago

Concept7Concept7

916

share|improve this question

asked 5 hours ago

Concept7Concept7

916

asked 5 hours ago

Concept7Concept7

916

asked 5 hours ago

Concept7Concept7

916

2 Answers
2

active

oldest

votes

4

You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'

documentclass[tikz,border=5mm]{standalone}

usepackage{tkz-euclide}

usetkzobj{all}

begin{document}

begin{tikzpicture}

coordinate[label=above right:$P_1$] (P1) at (.5,2);

coordinate[label=above right:$P_2$] (P2) at (2.5,0);

coordinate[label=right:$M$] (M) at (1.5,1);

coordinate (A) at (2,1.5);

pgfmathsetmacro{a}{.5-sqrt(2)}

pgfmathsetmacro{b}{.5+sqrt(12.5)}



shade[top color=white,bottom color=red!50,

transform canvas={rotate around={45:(.5,0)}}] 

(a,0) rectangle (b,.5);

draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};

draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};



draw (P1) -- (P2);

draw[red,thick] plot[domain=-.5:3] (x,{x-.5});

foreach p in {P1,P2,M}

fill (p) circle(1pt);

node at (1.5,3){(|z-z_1|leq|z-z_2| )};

tkzMarkRightAngle(P1,M,A)

end{tikzpicture}

end{document}

share|improve this answer

answered 4 hours ago

Black MildBlack Mild

697611

add a comment | 

2

This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.

documentclass[tikz]{standalone}

usetikzlibrary{calc,backgrounds}

usepackage{amsmath}

DeclareMathOperator{re}{Re}

DeclareMathOperator{im}{Im}

begin{document}

  begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;

    xmin=-1;xmax=3;}]

      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};

      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;

      path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}

      {(X,Y) coordinate[label=P:$L$] (L)};

      begin{scope}[on background layer]

      shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),

      n1={atan2(y2-y1,x2-x1)} in 

       [left color=white,right color=red,middle color=white,shading angle=n1]

       (p1) -- (p2)  --  ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)

        ;

      end{scope}   

      draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});

      draw (P_1) -- (P_2);

      node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};

  end{tikzpicture}

end{document}

share|improve this answer

edited 3 hours ago

answered 5 hours ago

marmotmarmot

111k5138257

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I like your answer, and the correction of re(x) and im(x) :).
  
  – manooooh
  16 mins ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f480985%2fhow-to-fade-a-semiplane-defined-by-line%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

4

You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'

documentclass[tikz,border=5mm]{standalone}

usepackage{tkz-euclide}

usetkzobj{all}

begin{document}

begin{tikzpicture}

coordinate[label=above right:$P_1$] (P1) at (.5,2);

coordinate[label=above right:$P_2$] (P2) at (2.5,0);

coordinate[label=right:$M$] (M) at (1.5,1);

coordinate (A) at (2,1.5);

pgfmathsetmacro{a}{.5-sqrt(2)}

pgfmathsetmacro{b}{.5+sqrt(12.5)}



shade[top color=white,bottom color=red!50,

transform canvas={rotate around={45:(.5,0)}}] 

(a,0) rectangle (b,.5);

draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};

draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};



draw (P1) -- (P2);

draw[red,thick] plot[domain=-.5:3] (x,{x-.5});

foreach p in {P1,P2,M}

fill (p) circle(1pt);

node at (1.5,3){(|z-z_1|leq|z-z_2| )};

tkzMarkRightAngle(P1,M,A)

end{tikzpicture}

end{document}

share|improve this answer

answered 4 hours ago

Black MildBlack Mild

697611

add a comment | 

4

You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'

documentclass[tikz,border=5mm]{standalone}

usepackage{tkz-euclide}

usetkzobj{all}

begin{document}

begin{tikzpicture}

coordinate[label=above right:$P_1$] (P1) at (.5,2);

coordinate[label=above right:$P_2$] (P2) at (2.5,0);

coordinate[label=right:$M$] (M) at (1.5,1);

coordinate (A) at (2,1.5);

pgfmathsetmacro{a}{.5-sqrt(2)}

pgfmathsetmacro{b}{.5+sqrt(12.5)}



shade[top color=white,bottom color=red!50,

transform canvas={rotate around={45:(.5,0)}}] 

(a,0) rectangle (b,.5);

draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};

draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};



draw (P1) -- (P2);

draw[red,thick] plot[domain=-.5:3] (x,{x-.5});

foreach p in {P1,P2,M}

fill (p) circle(1pt);

node at (1.5,3){(|z-z_1|leq|z-z_2| )};

tkzMarkRightAngle(P1,M,A)

end{tikzpicture}

end{document}

share|improve this answer

answered 4 hours ago

Black MildBlack Mild

697611

add a comment | 

You may rotate the shading area to the x-axis, shade, then rotate back with 'transform canvas'

documentclass[tikz,border=5mm]{standalone}

usepackage{tkz-euclide}

usetkzobj{all}

begin{document}

begin{tikzpicture}

coordinate[label=above right:$P_1$] (P1) at (.5,2);

coordinate[label=above right:$P_2$] (P2) at (2.5,0);

coordinate[label=right:$M$] (M) at (1.5,1);

coordinate (A) at (2,1.5);

pgfmathsetmacro{a}{.5-sqrt(2)}

pgfmathsetmacro{b}{.5+sqrt(12.5)}



shade[top color=white,bottom color=red!50,

transform canvas={rotate around={45:(.5,0)}}] 

(a,0) rectangle (b,.5);

draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};

draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};



draw (P1) -- (P2);

draw[red,thick] plot[domain=-.5:3] (x,{x-.5});

foreach p in {P1,P2,M}

fill (p) circle(1pt);

node at (1.5,3){(|z-z_1|leq|z-z_2| )};

tkzMarkRightAngle(P1,M,A)

end{tikzpicture}

end{document}

share|improve this answer

answered 4 hours ago

Black MildBlack Mild

697611

documentclass[tikz,border=5mm]{standalone}

usepackage{tkz-euclide}

usetkzobj{all}

begin{document}

begin{tikzpicture}

coordinate[label=above right:$P_1$] (P1) at (.5,2);

coordinate[label=above right:$P_2$] (P2) at (2.5,0);

coordinate[label=right:$M$] (M) at (1.5,1);

coordinate (A) at (2,1.5);

pgfmathsetmacro{a}{.5-sqrt(2)}

pgfmathsetmacro{b}{.5+sqrt(12.5)}



shade[top color=white,bottom color=red!50,

transform canvas={rotate around={45:(.5,0)}}] 

(a,0) rectangle (b,.5);

draw[-latex] (-1,0)--(3.5,0) node[below]{rm{Re}$(x)$};

draw[-latex] (0,-1)--(0,3.5) node[left]{rm{Im}$(x)$};



draw (P1) -- (P2);

draw[red,thick] plot[domain=-.5:3] (x,{x-.5});

foreach p in {P1,P2,M}

fill (p) circle(1pt);

node at (1.5,3){(|z-z_1|leq|z-z_2| )};

tkzMarkRightAngle(P1,M,A)

end{tikzpicture}

end{document}

share|improve this answer

answered 4 hours ago

Black MildBlack Mild

697611

answered 4 hours ago

Black MildBlack Mild

697611

answered 4 hours ago

Black MildBlack Mild

697611

2

This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.

documentclass[tikz]{standalone}

usetikzlibrary{calc,backgrounds}

usepackage{amsmath}

DeclareMathOperator{re}{Re}

DeclareMathOperator{im}{Im}

begin{document}

  begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;

    xmin=-1;xmax=3;}]

      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};

      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;

      path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}

      {(X,Y) coordinate[label=P:$L$] (L)};

      begin{scope}[on background layer]

      shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),

      n1={atan2(y2-y1,x2-x1)} in 

       [left color=white,right color=red,middle color=white,shading angle=n1]

       (p1) -- (p2)  --  ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)

        ;

      end{scope}   

      draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});

      draw (P_1) -- (P_2);

      node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};

  end{tikzpicture}

end{document}

share|improve this answer

edited 3 hours ago

answered 5 hours ago

marmotmarmot

111k5138257

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I like your answer, and the correction of re(x) and im(x) :).
  
  – manooooh
  16 mins ago
  

  
  
  
  

add a comment | 

2

This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.

documentclass[tikz]{standalone}

usetikzlibrary{calc,backgrounds}

usepackage{amsmath}

DeclareMathOperator{re}{Re}

DeclareMathOperator{im}{Im}

begin{document}

  begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;

    xmin=-1;xmax=3;}]

      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};

      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;

      path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}

      {(X,Y) coordinate[label=P:$L$] (L)};

      begin{scope}[on background layer]

      shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),

      n1={atan2(y2-y1,x2-x1)} in 

       [left color=white,right color=red,middle color=white,shading angle=n1]

       (p1) -- (p2)  --  ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)

        ;

      end{scope}   

      draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});

      draw (P_1) -- (P_2);

      node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};

  end{tikzpicture}

end{document}

share|improve this answer

edited 3 hours ago

answered 5 hours ago

marmotmarmot

111k5138257

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I like your answer, and the correction of re(x) and im(x) :).
  
  – manooooh
  16 mins ago
  

  
  
  
  

add a comment | 

This is in principle very simple but tkz-euclide seems to mess up things a bit. One can just use a shading angle, which can, of course, be computed by TikZ.

documentclass[tikz]{standalone}

usetikzlibrary{calc,backgrounds}

usepackage{amsmath}

DeclareMathOperator{re}{Re}

DeclareMathOperator{im}{Im}

begin{document}

  begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;

    xmin=-1;xmax=3;}]

      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};

      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;

      path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}

      {(X,Y) coordinate[label=P:$L$] (L)};

      begin{scope}[on background layer]

      shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),

      n1={atan2(y2-y1,x2-x1)} in 

       [left color=white,right color=red,middle color=white,shading angle=n1]

       (p1) -- (p2)  --  ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)

        ;

      end{scope}   

      draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});

      draw (P_1) -- (P_2);

      node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};

  end{tikzpicture}

end{document}

share|improve this answer

edited 3 hours ago

answered 5 hours ago

marmotmarmot

111k5138257

documentclass[tikz]{standalone}

usetikzlibrary{calc,backgrounds}

usepackage{amsmath}

DeclareMathOperator{re}{Re}

DeclareMathOperator{im}{Im}

begin{document}

  begin{tikzpicture}[anchor=center,declare function={f(x)=x-0.5;

    xmin=-1;xmax=3;}]

      draw[-latex] (-1.5,0) -- (3.5,0) node[below left]{$re z$};

      draw[-latex] (0,-1.5) -- (0,3.5) node[below left]{$im z$};;

      path foreach X/Y/L/P in {.5/2/P_1/45, 2.5/0/P_2/45, 1.5/1/M/0}

      {(X,Y) coordinate[label=P:$L$] (L)};

      begin{scope}[on background layer]

      shade let p1=({xmin},{f(xmin)}),p2=({xmax},{f(xmax)}),

      n1={atan2(y2-y1,x2-x1)} in 

       [left color=white,right color=red,middle color=white,shading angle=n1]

       (p1) -- (p2)  --  ($(p2)!2cm!-90:(p1)$) -- ($(p1)!2cm!90:(p2)$)

        ;

      end{scope}   

      draw[red,thick] plot[variable=x,domain=xmin:xmax] ({x},{f(x)});

      draw (P_1) -- (P_2);

      node[anchor=south,red] at (1.5,3) {$|z-z_1|leq|z-z_2| $};

  end{tikzpicture}

end{document}

share|improve this answer

edited 3 hours ago

answered 5 hours ago

marmotmarmot

111k5138257

answered 5 hours ago

marmotmarmot

111k5138257

answered 5 hours ago

marmotmarmot

111k5138257