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lookup file name in sql and rename file
Cannot start SQL Server PowerShellRename file in folder whenever it's created?Kill process, then uninstall application--Can I do this with PowerShell, over 400 computers, from a txt file?Rename displayName and CN from givenName and surName with Powershell?PowerShell won't rename an export .csv fileHow to retrieve list of unique file name parts?Powershell DSC File copy - Workgroup machinesPowershell privileges and execution policyRename AD computer member fails with “Cannot create a file when that file already exists”Delete file with powershell first 2 characters of the file name are the same
I am trying to use a Powershell script to use the account number in a file name and re-name with the ID number from a sql database. Below is the code I am using to attempt this and I am not getting the results I need. Please let me now if you have any suggestion or advise in getting this to work.
Thanks!!
File name = 111119999.docx
Table =
ID AccountNumber
5555 111119999
## Select Data from Database
function Select-Info($CliRef)
{
$conn = new-object System.Data.SqlClient.SqlConnection
$connstring = “provider=sqloledb;data source=[vmsvr039];initial catalog=[crs5_oltp];integrated security=SSPI”
$conn.connectionstring = $connstring
$conn.open()
$query = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd = New-Object System.Data.SqlClient.SqlCommand($sql,$conn)
$cmd.connection = $conn
$cmd.commandtext = $query
$result = $cmd.executenonquery()
$conn.close()
return $query
}
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the file names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each file name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $CliRef
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
powershell
bumped to the homepage by Community♦ 3 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
add a comment |
I am trying to use a Powershell script to use the account number in a file name and re-name with the ID number from a sql database. Below is the code I am using to attempt this and I am not getting the results I need. Please let me now if you have any suggestion or advise in getting this to work.
Thanks!!
File name = 111119999.docx
Table =
ID AccountNumber
5555 111119999
## Select Data from Database
function Select-Info($CliRef)
{
$conn = new-object System.Data.SqlClient.SqlConnection
$connstring = “provider=sqloledb;data source=[vmsvr039];initial catalog=[crs5_oltp];integrated security=SSPI”
$conn.connectionstring = $connstring
$conn.open()
$query = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd = New-Object System.Data.SqlClient.SqlCommand($sql,$conn)
$cmd.connection = $conn
$cmd.commandtext = $query
$result = $cmd.executenonquery()
$conn.close()
return $query
}
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the file names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each file name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $CliRef
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
powershell
bumped to the homepage by Community♦ 3 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28
add a comment |
I am trying to use a Powershell script to use the account number in a file name and re-name with the ID number from a sql database. Below is the code I am using to attempt this and I am not getting the results I need. Please let me now if you have any suggestion or advise in getting this to work.
Thanks!!
File name = 111119999.docx
Table =
ID AccountNumber
5555 111119999
## Select Data from Database
function Select-Info($CliRef)
{
$conn = new-object System.Data.SqlClient.SqlConnection
$connstring = “provider=sqloledb;data source=[vmsvr039];initial catalog=[crs5_oltp];integrated security=SSPI”
$conn.connectionstring = $connstring
$conn.open()
$query = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd = New-Object System.Data.SqlClient.SqlCommand($sql,$conn)
$cmd.connection = $conn
$cmd.commandtext = $query
$result = $cmd.executenonquery()
$conn.close()
return $query
}
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the file names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each file name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $CliRef
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
powershell
I am trying to use a Powershell script to use the account number in a file name and re-name with the ID number from a sql database. Below is the code I am using to attempt this and I am not getting the results I need. Please let me now if you have any suggestion or advise in getting this to work.
Thanks!!
File name = 111119999.docx
Table =
ID AccountNumber
5555 111119999
## Select Data from Database
function Select-Info($CliRef)
{
$conn = new-object System.Data.SqlClient.SqlConnection
$connstring = “provider=sqloledb;data source=[vmsvr039];initial catalog=[crs5_oltp];integrated security=SSPI”
$conn.connectionstring = $connstring
$conn.open()
$query = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd = New-Object System.Data.SqlClient.SqlCommand($sql,$conn)
$cmd.connection = $conn
$cmd.commandtext = $query
$result = $cmd.executenonquery()
$conn.close()
return $query
}
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the file names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each file name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $CliRef
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
powershell
powershell
edited Jan 21 '13 at 16:26
August
3,0641117
3,0641117
asked Jan 18 '13 at 17:02
timtim
1
1
bumped to the homepage by Community♦ 3 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
bumped to the homepage by Community♦ 3 mins ago
This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28
add a comment |
"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28
"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28
"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28
add a comment |
1 Answer
1
active
oldest
votes
By changing the $ID = Return-Info $CliRef to $ID = Return-Info $FiNm I was able to get this to work. The file name will also need to have the ".docx" removed.
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the image names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each Image name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $FiNm
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
add a comment |
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1 Answer
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1 Answer
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oldest
votes
By changing the $ID = Return-Info $CliRef to $ID = Return-Info $FiNm I was able to get this to work. The file name will also need to have the ".docx" removed.
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the image names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each Image name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $FiNm
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
add a comment |
By changing the $ID = Return-Info $CliRef to $ID = Return-Info $FiNm I was able to get this to work. The file name will also need to have the ".docx" removed.
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the image names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each Image name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $FiNm
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
add a comment |
By changing the $ID = Return-Info $CliRef to $ID = Return-Info $FiNm I was able to get this to work. The file name will also need to have the ".docx" removed.
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the image names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each Image name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $FiNm
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
By changing the $ID = Return-Info $CliRef to $ID = Return-Info $FiNm I was able to get this to work. The file name will also need to have the ".docx" removed.
## Return ID from Database
function Return-Info($CliRef)
{
$conn = New-Object System.Data.SqlClient.SqlConnection
$conn.ConnectionString = "Server=vmsvr039;Database=crs5_oltp;Integrated Security=SSPI;"
$conn.Open()
$cmd = New-Object System.Data.SqlClient.SqlCommand
$cmd.commandtext = “Select convert(varchar,cnsmr_accnt_idntfr_agncy_id) as ID FROM cnsmr_accnt WHERE cnsmr_accnt_crdtr_rfrnc_id_txt = '$CliRef'”
$cmd.connection = $conn
$result = $cmd.ExecuteScalar()
$conn.close()
return $result
}
## Collect the image names
$FiNms = Get-ChildItem H:pstest -Name
## Loop through each Image name
foreach ($FiNm in $FiNms)
{
## Variable for current File path
$file = “H:pstest” + $FiNm
## Variable for new File path
$newFile = “H:psrenamed” + $FiNm
$ID = Return-Info $FiNm
$ID = $ID + “.docx”
Copy-Item $file -Destination $newFile
Rename-Item $file $ID -force
}
edited Jan 21 '13 at 17:01
August
3,0641117
3,0641117
answered Jan 21 '13 at 16:55
timtim
1
1
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
add a comment |
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
please use the Code Sample formatting in the future to make it easier to read when pasting a script or other code - this is the {} symbol in the menu above where you type a question/answer
– August
Jan 21 '13 at 17:01
add a comment |
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"I am not getting the results I need" - describe what you ARE getting and maybe someone will try to help you.
– August
Jan 21 '13 at 16:28