Ryfujk

Drawing ramified coverings with tikz

What does "Scientists rise up against statistical significance" mean? (Comment in Nature)

250 Floor Tower

Is it possible to have a strip of cold climate in the middle of a planet?

Why should universal income be universal?

Did arcade monitors have same pixel aspect ratio as TV sets?

Start making guitar arrangements

Is there any references on the tensor product of presentable (1-)categories?

Why did the EU agree to delay the Brexit deadline?

L1 and Ln cache: when are they written?

lightning-datatable row number error

Melting point of aspirin, contradicting sources

The IT department bottlenecks progress. How should I handle this?

What does routing an IP address mean?

Freedom of speech and where it applies

Did Swami Prabhupada reject Advaita?

How do you respond to a colleague from another team when they're wrongly expecting that you'll help them?

Is there a name for this algorithm to calculate the concentration of a mixture of two solutions containing the same solute?

Why can Carol Danvers change her suit colours in the first place?

Why did the Mercure fail?

Travelling outside the UK without a passport

Lowest total scrabble score

copy and scale one figure (wheel)

What should you do if you miss a job interview (deliberately)?

Drawing ramified coverings with tikz

Rotate a node but not its content: the case of the ellipse decorationNumerical conditional within tikz keys?How to draw up this hierarchical diagram?(Or similar way)TikZ: Drawing an arc from an intersection to an intersectionDrawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themProblems with nested TikZpicturesHow to place nodes in an absolute coordinate system in tikzHow to draw a Block Diagram like thisTikZ picture not centered in figure fbox

2

1

I want to draw a diagram similar to this one:

For that I started with the following code:

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,0) -- (7,0);

draw[thick] (1,2) -- (7,2);

draw[thick] (1,2.5) -- (7,2.5);

draw[thick] (1,1.5) -- (7,1.5);

end{tikzpicture}

The only thing that I don't know how to do is the curvy parts. I would appreciate some indication.

tikz-pgf

share|improve this question

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

add a comment | 

2

1

I want to draw a diagram similar to this one:

For that I started with the following code:

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,0) -- (7,0);

draw[thick] (1,2) -- (7,2);

draw[thick] (1,2.5) -- (7,2.5);

draw[thick] (1,1.5) -- (7,1.5);

end{tikzpicture}

The only thing that I don't know how to do is the curvy parts. I would appreciate some indication.

tikz-pgf

share|improve this question

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

add a comment | 

I want to draw a diagram similar to this one:

For that I started with the following code:

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,0) -- (7,0);

draw[thick] (1,2) -- (7,2);

draw[thick] (1,2.5) -- (7,2.5);

draw[thick] (1,1.5) -- (7,1.5);

end{tikzpicture}

The only thing that I don't know how to do is the curvy parts. I would appreciate some indication.

tikz-pgf

share|improve this question

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,0) -- (7,0);

draw[thick] (1,2) -- (7,2);

draw[thick] (1,2.5) -- (7,2.5);

draw[thick] (1,1.5) -- (7,1.5);

end{tikzpicture}

share|improve this question

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

share|improve this question

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

edited 2 hours ago

Cragfelt

2,96531028

edited 2 hours ago

Cragfelt

2,96531028

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

asked 2 hours ago

Gabriel RibeiroGabriel Ribeiro

25918

2 Answers
2

active

oldest

votes

3

The following is a pretty manual way to do this. I only did it for the first two lines, I hope you can apply it to the other occurrences. It uses the in and out keys of the to path construction:

documentclass[tikz]{standalone}



begin{document}

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,2.5) -- (7,2.5) coordinate(a);

draw[thick] (1,2) -- (7,2) coordinate(b);

draw[thick] (1,1.5) -- (7,1.5) coordinate(c);

draw[thick] (1,0) -- (7,0) coordinate(d);

draw[thick]

  (a) ++(.25,-.25) coordinate(ab) to[out=180,in=0] (a)

  (ab) to[out=180,in=0] (b)

  (ab) to[out=0,in=180] ++(.25,.25)

  (ab) to[out=0,in=180] ++(.25,-.25)

  ;

filldraw

  (ab) circle(.05)

  ;

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

SkillmonSkillmon

23.6k12247

add a comment | 

1

This uses the same in and out trick as Skillmon and puts it into a style dip, which takes as arguments the horizontal position and the depth, where the sign decides whether the dip is a dip (minus) or a bump (plus).

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}

newcounter{dip}

begin{document}

begin{tikzpicture}[dip/.style args={#1/#2}{/utils/exec=stepcounter{dip},

insert path={%

coordinate (aux1) ({#1-abs(#2)},0) coordinate (aux2) ({#1+abs(#2)},0) coordinate (aux3)

(aux1) -- (aux2|-aux1) to[out=0,in=180]  

++({abs(#2)},#2) coordinate(dip-thevalue{dip}) to[out=0,in=180]  (aux3|-aux1)

}}]

begin{scope}[thick,local bounding box=dips]

 draw (1,2.5) [dip=5.5cm/-2.5mm]-- (7,2.5);

 fill (dip-1) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,2) [dip/.list={2.5cm/-2.5mm,5.5cm/2.5mm}] -- (7,2);

 fill (dip-2) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,1.5) [dip/.list={2.5cm/2.5mm,5.5cm/-5mm}]  -- (7,1.5);

 fill (dip-5) circle[radius=2pt] node[above right=0pt and 5pt]{$b=2$};

 draw (1,1) -- (7,1);

 draw (1,0.5) [dip=5.5cm/5mm]  -- (7,0.5);

end{scope}

path (dips.north west) node[anchor=north east] (X) {$X$};

path (dips.south west) node[anchor=south east] (Y) {$Y$};

draw[<-] (Y) -- (X) node[left, midway] {$f$};

end{tikzpicture}

end{document}

share|improve this answer

answered 12 mins ago

marmotmarmot

111k5138260

add a comment | 

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f481125%2fdrawing-ramified-coverings-with-tikz%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

3

The following is a pretty manual way to do this. I only did it for the first two lines, I hope you can apply it to the other occurrences. It uses the in and out keys of the to path construction:

documentclass[tikz]{standalone}



begin{document}

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,2.5) -- (7,2.5) coordinate(a);

draw[thick] (1,2) -- (7,2) coordinate(b);

draw[thick] (1,1.5) -- (7,1.5) coordinate(c);

draw[thick] (1,0) -- (7,0) coordinate(d);

draw[thick]

  (a) ++(.25,-.25) coordinate(ab) to[out=180,in=0] (a)

  (ab) to[out=180,in=0] (b)

  (ab) to[out=0,in=180] ++(.25,.25)

  (ab) to[out=0,in=180] ++(.25,-.25)

  ;

filldraw

  (ab) circle(.05)

  ;

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

SkillmonSkillmon

23.6k12247

add a comment | 

3

The following is a pretty manual way to do this. I only did it for the first two lines, I hope you can apply it to the other occurrences. It uses the in and out keys of the to path construction:

documentclass[tikz]{standalone}



begin{document}

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,2.5) -- (7,2.5) coordinate(a);

draw[thick] (1,2) -- (7,2) coordinate(b);

draw[thick] (1,1.5) -- (7,1.5) coordinate(c);

draw[thick] (1,0) -- (7,0) coordinate(d);

draw[thick]

  (a) ++(.25,-.25) coordinate(ab) to[out=180,in=0] (a)

  (ab) to[out=180,in=0] (b)

  (ab) to[out=0,in=180] ++(.25,.25)

  (ab) to[out=0,in=180] ++(.25,-.25)

  ;

filldraw

  (ab) circle(.05)

  ;

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

SkillmonSkillmon

23.6k12247

add a comment | 

The following is a pretty manual way to do this. I only did it for the first two lines, I hope you can apply it to the other occurrences. It uses the in and out keys of the to path construction:

documentclass[tikz]{standalone}



begin{document}

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,2.5) -- (7,2.5) coordinate(a);

draw[thick] (1,2) -- (7,2) coordinate(b);

draw[thick] (1,1.5) -- (7,1.5) coordinate(c);

draw[thick] (1,0) -- (7,0) coordinate(d);

draw[thick]

  (a) ++(.25,-.25) coordinate(ab) to[out=180,in=0] (a)

  (ab) to[out=180,in=0] (b)

  (ab) to[out=0,in=180] ++(.25,.25)

  (ab) to[out=0,in=180] ++(.25,-.25)

  ;

filldraw

  (ab) circle(.05)

  ;

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

SkillmonSkillmon

23.6k12247

documentclass[tikz]{standalone}



begin{document}

begin{tikzpicture}

draw (0,0) node {$Y$};

draw (0,2) node {$X$};

draw[<-] (0,0.35) -- (0,1.65) node[left, midway] {$f$};

draw[thick] (1,2.5) -- (7,2.5) coordinate(a);

draw[thick] (1,2) -- (7,2) coordinate(b);

draw[thick] (1,1.5) -- (7,1.5) coordinate(c);

draw[thick] (1,0) -- (7,0) coordinate(d);

draw[thick]

  (a) ++(.25,-.25) coordinate(ab) to[out=180,in=0] (a)

  (ab) to[out=180,in=0] (b)

  (ab) to[out=0,in=180] ++(.25,.25)

  (ab) to[out=0,in=180] ++(.25,-.25)

  ;

filldraw

  (ab) circle(.05)

  ;

end{tikzpicture}

end{document}

share|improve this answer

edited 1 hour ago

answered 1 hour ago

SkillmonSkillmon

23.6k12247

answered 1 hour ago

SkillmonSkillmon

23.6k12247

answered 1 hour ago

SkillmonSkillmon

23.6k12247

1

This uses the same in and out trick as Skillmon and puts it into a style dip, which takes as arguments the horizontal position and the depth, where the sign decides whether the dip is a dip (minus) or a bump (plus).

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}

newcounter{dip}

begin{document}

begin{tikzpicture}[dip/.style args={#1/#2}{/utils/exec=stepcounter{dip},

insert path={%

coordinate (aux1) ({#1-abs(#2)},0) coordinate (aux2) ({#1+abs(#2)},0) coordinate (aux3)

(aux1) -- (aux2|-aux1) to[out=0,in=180]  

++({abs(#2)},#2) coordinate(dip-thevalue{dip}) to[out=0,in=180]  (aux3|-aux1)

}}]

begin{scope}[thick,local bounding box=dips]

 draw (1,2.5) [dip=5.5cm/-2.5mm]-- (7,2.5);

 fill (dip-1) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,2) [dip/.list={2.5cm/-2.5mm,5.5cm/2.5mm}] -- (7,2);

 fill (dip-2) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,1.5) [dip/.list={2.5cm/2.5mm,5.5cm/-5mm}]  -- (7,1.5);

 fill (dip-5) circle[radius=2pt] node[above right=0pt and 5pt]{$b=2$};

 draw (1,1) -- (7,1);

 draw (1,0.5) [dip=5.5cm/5mm]  -- (7,0.5);

end{scope}

path (dips.north west) node[anchor=north east] (X) {$X$};

path (dips.south west) node[anchor=south east] (Y) {$Y$};

draw[<-] (Y) -- (X) node[left, midway] {$f$};

end{tikzpicture}

end{document}

share|improve this answer

answered 12 mins ago

marmotmarmot

111k5138260

add a comment | 

1

This uses the same in and out trick as Skillmon and puts it into a style dip, which takes as arguments the horizontal position and the depth, where the sign decides whether the dip is a dip (minus) or a bump (plus).

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}

newcounter{dip}

begin{document}

begin{tikzpicture}[dip/.style args={#1/#2}{/utils/exec=stepcounter{dip},

insert path={%

coordinate (aux1) ({#1-abs(#2)},0) coordinate (aux2) ({#1+abs(#2)},0) coordinate (aux3)

(aux1) -- (aux2|-aux1) to[out=0,in=180]  

++({abs(#2)},#2) coordinate(dip-thevalue{dip}) to[out=0,in=180]  (aux3|-aux1)

}}]

begin{scope}[thick,local bounding box=dips]

 draw (1,2.5) [dip=5.5cm/-2.5mm]-- (7,2.5);

 fill (dip-1) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,2) [dip/.list={2.5cm/-2.5mm,5.5cm/2.5mm}] -- (7,2);

 fill (dip-2) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,1.5) [dip/.list={2.5cm/2.5mm,5.5cm/-5mm}]  -- (7,1.5);

 fill (dip-5) circle[radius=2pt] node[above right=0pt and 5pt]{$b=2$};

 draw (1,1) -- (7,1);

 draw (1,0.5) [dip=5.5cm/5mm]  -- (7,0.5);

end{scope}

path (dips.north west) node[anchor=north east] (X) {$X$};

path (dips.south west) node[anchor=south east] (Y) {$Y$};

draw[<-] (Y) -- (X) node[left, midway] {$f$};

end{tikzpicture}

end{document}

share|improve this answer

answered 12 mins ago

marmotmarmot

111k5138260

add a comment | 

This uses the same in and out trick as Skillmon and puts it into a style dip, which takes as arguments the horizontal position and the depth, where the sign decides whether the dip is a dip (minus) or a bump (plus).

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}

newcounter{dip}

begin{document}

begin{tikzpicture}[dip/.style args={#1/#2}{/utils/exec=stepcounter{dip},

insert path={%

coordinate (aux1) ({#1-abs(#2)},0) coordinate (aux2) ({#1+abs(#2)},0) coordinate (aux3)

(aux1) -- (aux2|-aux1) to[out=0,in=180]  

++({abs(#2)},#2) coordinate(dip-thevalue{dip}) to[out=0,in=180]  (aux3|-aux1)

}}]

begin{scope}[thick,local bounding box=dips]

 draw (1,2.5) [dip=5.5cm/-2.5mm]-- (7,2.5);

 fill (dip-1) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,2) [dip/.list={2.5cm/-2.5mm,5.5cm/2.5mm}] -- (7,2);

 fill (dip-2) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,1.5) [dip/.list={2.5cm/2.5mm,5.5cm/-5mm}]  -- (7,1.5);

 fill (dip-5) circle[radius=2pt] node[above right=0pt and 5pt]{$b=2$};

 draw (1,1) -- (7,1);

 draw (1,0.5) [dip=5.5cm/5mm]  -- (7,0.5);

end{scope}

path (dips.north west) node[anchor=north east] (X) {$X$};

path (dips.south west) node[anchor=south east] (Y) {$Y$};

draw[<-] (Y) -- (X) node[left, midway] {$f$};

end{tikzpicture}

end{document}

share|improve this answer

answered 12 mins ago

marmotmarmot

111k5138260

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}

newcounter{dip}

begin{document}

begin{tikzpicture}[dip/.style args={#1/#2}{/utils/exec=stepcounter{dip},

insert path={%

coordinate (aux1) ({#1-abs(#2)},0) coordinate (aux2) ({#1+abs(#2)},0) coordinate (aux3)

(aux1) -- (aux2|-aux1) to[out=0,in=180]  

++({abs(#2)},#2) coordinate(dip-thevalue{dip}) to[out=0,in=180]  (aux3|-aux1)

}}]

begin{scope}[thick,local bounding box=dips]

 draw (1,2.5) [dip=5.5cm/-2.5mm]-- (7,2.5);

 fill (dip-1) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,2) [dip/.list={2.5cm/-2.5mm,5.5cm/2.5mm}] -- (7,2);

 fill (dip-2) circle[radius=2pt] node[right=3pt]{$b=1$};

 draw (1,1.5) [dip/.list={2.5cm/2.5mm,5.5cm/-5mm}]  -- (7,1.5);

 fill (dip-5) circle[radius=2pt] node[above right=0pt and 5pt]{$b=2$};

 draw (1,1) -- (7,1);

 draw (1,0.5) [dip=5.5cm/5mm]  -- (7,0.5);

end{scope}

path (dips.north west) node[anchor=north east] (X) {$X$};

path (dips.south west) node[anchor=south east] (Y) {$Y$};

draw[<-] (Y) -- (X) node[left, midway] {$f$};

end{tikzpicture}

end{document}

share|improve this answer

answered 12 mins ago

marmotmarmot

111k5138260

answered 12 mins ago

marmotmarmot

111k5138260

answered 12 mins ago

marmotmarmot

111k5138260