Ryfujk

Did Swami Prabhupada reject Advaita?

Delivering sarcasm

Yosemite Fire Rings - What to Expect?

Are the IPv6 address space and IPv4 address space completely disjoint?

Did arcade monitors have same pixel aspect ratio as TV sets?

Count the occurrence of each unique word in the file

Longest common substring in linear time

Why should universal income be universal?

Loading commands from file

Are paving bricks differently sized for sand bedding vs mortar bedding?

Melting point of aspirin, contradicting sources

What does chmod -u do?

Pre-mixing cryogenic fuels and using only one fuel tank

Why did the EU agree to delay the Brexit deadline?

How do I find all files that end with a dot

Is it possible to have a strip of cold climate in the middle of a planet?

How could a planet have erratic days?

Fear of getting stuck on one programming language / technology that is not used in my country

Why Shazam when there is already Superman?

How do I color the graph in datavisualization?

What should you do when eye contact makes your subordinate uncomfortable?

Non-trope happy ending?

Offered money to buy a house, seller is asking for more to cover gap between their listing and mortgage owed

Is it safe to use olive oil to clean the ear wax?

GraphicsGrid with a Label for each Column and Row

Putting a vertical line in each Histogram using GraphicsGridComposite graphics with Row, Column, data aggregation and layout controlControl objects Sizing and placement in Graphicsgrid Vs Grid:Label each panel of GridCombining ArrayPlot and PlotGraphicsGrid Format Problem with SpanFromAboveConstructing a grid from a matrixHow to solve for the intersection points of two ellipses?How to use GraphicsGrid with ListPlots that have a PlotLegend?Rotated Row and Normal Column Headings for a GridPutting a vertical line in each Histogram using GraphicsGrid

3

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

$endgroup$

add a comment | 

3

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

$endgroup$

add a comment | 

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

$endgroup$

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,084919

3 Answers
3

active

oldest

votes

3

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share|improve this answer

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

2

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 3 hours ago

MelaGoMelaGo

4963

$endgroup$

add a comment | 

2

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

$endgroup$

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193846%2fgraphicsgrid-with-a-label-for-each-column-and-row%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

3

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share|improve this answer

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

3

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share|improve this answer

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share|improve this answer

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share|improve this answer

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

answered 29 mins ago

m_goldbergm_goldberg

87.7k872198

2

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 3 hours ago

MelaGoMelaGo

4963

$endgroup$

add a comment | 

2

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 3 hours ago

MelaGoMelaGo

4963

$endgroup$

add a comment | 

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 3 hours ago

MelaGoMelaGo

4963

$endgroup$

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 3 hours ago

MelaGoMelaGo

4963

answered 3 hours ago

MelaGoMelaGo

4963

answered 3 hours ago

MelaGoMelaGo

4963

2

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

$endgroup$

add a comment | 

2

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

$endgroup$

add a comment | 

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

$endgroup$

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213

answered 3 hours ago

Rohit NamjoshiRohit Namjoshi

1,4921213