Ryfujk

A variation to the phrase "hanging over my shoulders"

How to convince somebody that he is fit for something else, but not this job?

Can you use Vicious Mockery to win an argument or gain favours?

Does "he squandered his car on drink" sound natural?

What are some good ways to treat frozen vegetables such that they behave like fresh vegetables when stir frying them?

Is there a way to have vectors outlined in a Vector Plot?

Is this part of the description of the Archfey warlock's Misty Escape feature redundant?

Why is so much work done on numerical verification of the Riemann Hypothesis?

Taxes on Dividends in a Roth IRA

Is there a nicer/politer/more positive alternative for "negates"?

awk assign to multiple variables at once

A Trivial Diagnosis

How much of a Devil Fruit must be consumed to gain the power?

Quoting Keynes in a lecture

What is the English pronunciation of "pain au chocolat"?

Did the UK lift the requirement for registering SIM cards?

Has any country ever had 2 former presidents in jail simultaneously?

C++ copy constructor called at return

Why do ¬, ∀ and ∃ have the same precedence?

It grows, but water kills it

Is there a RAID 0 Equivalent for RAM?

Does an advisor owe his/her student anything? Will an advisor keep a PhD student only out of pity?

Why is it that I can sometimes guess the next note?

Why is the Sun approximated as a black body at ~ 5800 K?

Is there a way to have vectors outlined in a Vector Plot?

How do I fill in a circle made by ParametricPlot with one solid color?Using PlotLegendsModule Returns Two Values for Plot; I need to Color themFilling the area between two curves, only where and if the second lies above the first oneScaling vectors in an animated vector fieldIs there any way to plot function from other function?ContourPlot with BarLegend: vector format export problemHow should I edit my code to produce a particular type of image?On the exporting process from Mathematica in vector graphicHow to use vector plot and gradient vectors?

1

$begingroup$

I am using the following code to make a 3D vector plot.

VectorPlot3D[{

  x (1 - x) - x*y,

  y (1 - y) + x*y - y*z,

  z (1 - z) + y*z},

 {x, 0, 1.2},

 {y, 0, 1.2},

 {z, 0, 1.2},

 Axes -> True, AxesLabel -> {"x", "y", "z"},

 VectorColorFunction -> "Rainbow",

 VectorScale -> {0.05, 0.7, None}]

This makes a bunch of vectors, but the entire vector is colored. Is there a way I can use VectorStyle or another option to make each vector have a black outline, but have the inside of the area filled in with the appropriate color?

plotting

share|improve this question

asked 1 hour ago

jeanquiltjeanquilt

1084

$endgroup$

add a comment | 

1

$begingroup$

I am using the following code to make a 3D vector plot.

VectorPlot3D[{

  x (1 - x) - x*y,

  y (1 - y) + x*y - y*z,

  z (1 - z) + y*z},

 {x, 0, 1.2},

 {y, 0, 1.2},

 {z, 0, 1.2},

 Axes -> True, AxesLabel -> {"x", "y", "z"},

 VectorColorFunction -> "Rainbow",

 VectorScale -> {0.05, 0.7, None}]

This makes a bunch of vectors, but the entire vector is colored. Is there a way I can use VectorStyle or another option to make each vector have a black outline, but have the inside of the area filled in with the appropriate color?

plotting

share|improve this question

asked 1 hour ago

jeanquiltjeanquilt

1084

$endgroup$

add a comment | 

$begingroup$

I am using the following code to make a 3D vector plot.

VectorPlot3D[{

  x (1 - x) - x*y,

  y (1 - y) + x*y - y*z,

  z (1 - z) + y*z},

 {x, 0, 1.2},

 {y, 0, 1.2},

 {z, 0, 1.2},

 Axes -> True, AxesLabel -> {"x", "y", "z"},

 VectorColorFunction -> "Rainbow",

 VectorScale -> {0.05, 0.7, None}]

This makes a bunch of vectors, but the entire vector is colored. Is there a way I can use VectorStyle or another option to make each vector have a black outline, but have the inside of the area filled in with the appropriate color?

plotting

share|improve this question

asked 1 hour ago

jeanquiltjeanquilt

1084

$endgroup$

VectorPlot3D[{

  x (1 - x) - x*y,

  y (1 - y) + x*y - y*z,

  z (1 - z) + y*z},

 {x, 0, 1.2},

 {y, 0, 1.2},

 {z, 0, 1.2},

 Axes -> True, AxesLabel -> {"x", "y", "z"},

 VectorColorFunction -> "Rainbow",

 VectorScale -> {0.05, 0.7, None}]

share|improve this question

asked 1 hour ago

jeanquiltjeanquilt

1084

share|improve this question

asked 1 hour ago

jeanquiltjeanquilt

1084

asked 1 hour ago

jeanquiltjeanquilt

1084

asked 1 hour ago

jeanquiltjeanquilt

1084

1 Answer
1

active

oldest

votes

3

$begingroup$

You can use Graphics to define any shape for drawing the vectors. Something like this:

VectorPlot3D[{x (1 - x) - x*y, y (1 - y) + x*y - y*z, 

  z (1 - z) + y*z}, {x, 0, 1.2}, {y, 0, 1.2}, {z, 0, 1.2}, 

 Axes -> True, AxesLabel -> {"x", "y", "z"}, 

 VectorColorFunction -> "Rainbow", VectorPoints -> 5, VectorScale -> {0.03, .7, None}, 

 VectorStyle -> Graphics[{EdgeForm[Black], Rectangle[{-2, -.2}, {0, .2}], 

    Polygon[{{0, .5}, {Sqrt[3], 0}, {0, -.5}}]}]]

share|improve this answer

answered 33 mins ago

MelaGoMelaGo

3613

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you! This is exactly how I wanted the plot to look!
  $endgroup$
  – jeanquilt
  7 mins ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193739%2fis-there-a-way-to-have-vectors-outlined-in-a-vector-plot%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

3

$begingroup$

You can use Graphics to define any shape for drawing the vectors. Something like this:

VectorPlot3D[{x (1 - x) - x*y, y (1 - y) + x*y - y*z, 

  z (1 - z) + y*z}, {x, 0, 1.2}, {y, 0, 1.2}, {z, 0, 1.2}, 

 Axes -> True, AxesLabel -> {"x", "y", "z"}, 

 VectorColorFunction -> "Rainbow", VectorPoints -> 5, VectorScale -> {0.03, .7, None}, 

 VectorStyle -> Graphics[{EdgeForm[Black], Rectangle[{-2, -.2}, {0, .2}], 

    Polygon[{{0, .5}, {Sqrt[3], 0}, {0, -.5}}]}]]

share|improve this answer

answered 33 mins ago

MelaGoMelaGo

3613

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you! This is exactly how I wanted the plot to look!
  $endgroup$
  – jeanquilt
  7 mins ago
  

  
  
  
  

add a comment | 

3

$begingroup$

You can use Graphics to define any shape for drawing the vectors. Something like this:

VectorPlot3D[{x (1 - x) - x*y, y (1 - y) + x*y - y*z, 

  z (1 - z) + y*z}, {x, 0, 1.2}, {y, 0, 1.2}, {z, 0, 1.2}, 

 Axes -> True, AxesLabel -> {"x", "y", "z"}, 

 VectorColorFunction -> "Rainbow", VectorPoints -> 5, VectorScale -> {0.03, .7, None}, 

 VectorStyle -> Graphics[{EdgeForm[Black], Rectangle[{-2, -.2}, {0, .2}], 

    Polygon[{{0, .5}, {Sqrt[3], 0}, {0, -.5}}]}]]

share|improve this answer

answered 33 mins ago

MelaGoMelaGo

3613

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Thank you! This is exactly how I wanted the plot to look!
  $endgroup$
  – jeanquilt
  7 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

You can use Graphics to define any shape for drawing the vectors. Something like this:

VectorPlot3D[{x (1 - x) - x*y, y (1 - y) + x*y - y*z, 

  z (1 - z) + y*z}, {x, 0, 1.2}, {y, 0, 1.2}, {z, 0, 1.2}, 

 Axes -> True, AxesLabel -> {"x", "y", "z"}, 

 VectorColorFunction -> "Rainbow", VectorPoints -> 5, VectorScale -> {0.03, .7, None}, 

 VectorStyle -> Graphics[{EdgeForm[Black], Rectangle[{-2, -.2}, {0, .2}], 

    Polygon[{{0, .5}, {Sqrt[3], 0}, {0, -.5}}]}]]

share|improve this answer

answered 33 mins ago

MelaGoMelaGo

3613

$endgroup$

VectorPlot3D[{x (1 - x) - x*y, y (1 - y) + x*y - y*z, 

  z (1 - z) + y*z}, {x, 0, 1.2}, {y, 0, 1.2}, {z, 0, 1.2}, 

 Axes -> True, AxesLabel -> {"x", "y", "z"}, 

 VectorColorFunction -> "Rainbow", VectorPoints -> 5, VectorScale -> {0.03, .7, None}, 

 VectorStyle -> Graphics[{EdgeForm[Black], Rectangle[{-2, -.2}, {0, .2}], 

    Polygon[{{0, .5}, {Sqrt[3], 0}, {0, -.5}}]}]]

share|improve this answer

answered 33 mins ago

MelaGoMelaGo

3613

answered 33 mins ago

MelaGoMelaGo

3613

answered 33 mins ago

MelaGoMelaGo

3613