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What is the highest possible scrabble score for placing a single tile
Craft the longest Scrabble sentenceScrabble ImpossibilitiesHighest possible score my friend could earn in one Scrabble turn?What is the longest word that can be made out of all the scrabble tiles?
$begingroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard Norh-American rules.
scrabble
asked 7 hours ago
user3294068user3294068
5,6741527
$endgroup$
add a comment |
$begingroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard Norh-American rules.
scrabble
asked 7 hours ago
user3294068user3294068
5,6741527
$endgroup$
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago
add a comment |
$begingroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard Norh-American rules.
scrabble
asked 7 hours ago
user3294068user3294068
5,6741527
$endgroup$
What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard Norh-American rules.
scrabble
scrabble
asked 7 hours ago
user3294068user3294068
5,6741527
asked 7 hours ago
user3294068user3294068
5,6741527
asked 7 hours ago
user3294068user3294068
5,6741527
asked 7 hours ago
user3294068user3294068
5,6741527
asked 7 hours ago
user3294068user3294068
5,6741527
5,6741527
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago
add a comment |
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:
...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...
...is 303 points.
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
$endgroup$
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
|
show 3 more comments
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:
...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...
...is 303 points.
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
$endgroup$
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
|
show 3 more comments
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:
...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...
...is 303 points.
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
$endgroup$
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
|
show 3 more comments
$begingroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:
...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...
...is 303 points.
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
$endgroup$
According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:
...However, that's not the best you can do. We're looking at the highest possible score.
The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.
So, with particularly cooperative (or particularly stupid) players, the best you can do...
...is 303 points.
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
answered 6 hours ago
Deusovi♦Deusovi
62.2k6214268
62.2k6214268
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
|
show 3 more comments
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
$begingroup$
I think that the 171 is what the questioner is looking for - " Assume language is English, using standard Norh[sic]-American rules."
$endgroup$
– Brandon_J
6 hours ago
2
2
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
6 hours ago
2
2
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
5 hours ago
1
1
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
38 mins ago
1
1
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
9 mins ago
|
show 3 more comments
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$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
7 hours ago
$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
7 hours ago