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Why does Starman/Roadster have radial acceleration?

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11

$begingroup$

Discussion in chat pointed out that the SpaceX Roadster or Starman has a Marsden A1 coefficient.

From solution 10 in Horizons:

 EPOCH= 2458164.5

  EC= .2585469914787243  QR= .9860596231806226  TP= 2458153.620483722645

  OM= 317.3549094214575  W = 177.3203028023227  IN= 1.088451292866039

  A1= 2.960683526738534E-9  R0= 1.  ALN= 1.  NM= 2.  NK= 0.

  SRC= -2.057839421666802E-7...

I wrote about the Marsden parameters in this question a while ago and have linked several sources there. You have to use that in a certain power-law equation and use units of days and AU, so A1 is 2.96E-09 AU/day^2.

Question: Why does Starman/Roadster have radial acceleration? What is causing this? Can the size of the acceleration be understood quantitatively?

Aliens are trying, very slowly, to steal it?

Air leaking out of the tires?

orbital-mechanics spacex tesla-roadster

share|improve this question

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

$endgroup$

add a comment | 

11

$begingroup$

Discussion in chat pointed out that the SpaceX Roadster or Starman has a Marsden A1 coefficient.

From solution 10 in Horizons:

 EPOCH= 2458164.5

  EC= .2585469914787243  QR= .9860596231806226  TP= 2458153.620483722645

  OM= 317.3549094214575  W = 177.3203028023227  IN= 1.088451292866039

  A1= 2.960683526738534E-9  R0= 1.  ALN= 1.  NM= 2.  NK= 0.

  SRC= -2.057839421666802E-7...

I wrote about the Marsden parameters in this question a while ago and have linked several sources there. You have to use that in a certain power-law equation and use units of days and AU, so A1 is 2.96E-09 AU/day^2.

Question: Why does Starman/Roadster have radial acceleration? What is causing this? Can the size of the acceleration be understood quantitatively?

Aliens are trying, very slowly, to steal it?

Air leaking out of the tires?

orbital-mechanics spacex tesla-roadster

share|improve this question

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

$endgroup$

add a comment | 

$begingroup$

Discussion in chat pointed out that the SpaceX Roadster or Starman has a Marsden A1 coefficient.

From solution 10 in Horizons:

 EPOCH= 2458164.5

  EC= .2585469914787243  QR= .9860596231806226  TP= 2458153.620483722645

  OM= 317.3549094214575  W = 177.3203028023227  IN= 1.088451292866039

  A1= 2.960683526738534E-9  R0= 1.  ALN= 1.  NM= 2.  NK= 0.

  SRC= -2.057839421666802E-7...

I wrote about the Marsden parameters in this question a while ago and have linked several sources there. You have to use that in a certain power-law equation and use units of days and AU, so A1 is 2.96E-09 AU/day^2.

Question: Why does Starman/Roadster have radial acceleration? What is causing this? Can the size of the acceleration be understood quantitatively?

Aliens are trying, very slowly, to steal it?

Air leaking out of the tires?

orbital-mechanics spacex tesla-roadster

share|improve this question

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

$endgroup$

 EPOCH= 2458164.5

  EC= .2585469914787243  QR= .9860596231806226  TP= 2458153.620483722645

  OM= 317.3549094214575  W = 177.3203028023227  IN= 1.088451292866039

  A1= 2.960683526738534E-9  R0= 1.  ALN= 1.  NM= 2.  NK= 0.

  SRC= -2.057839421666802E-7...

share|improve this question

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

share|improve this question

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

edited 4 hours ago

PearsonArtPhoto♦

82.7k16235450

asked 9 hours ago

uhohuhoh

37.6k18136480

asked 9 hours ago

uhohuhoh

37.6k18136480

1 Answer
1

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13

$begingroup$

Sunlight pressure. The acceleration is 9.08 μN / m² (Assuming perfect reflectivity). The size is about 3.66* 12.6 = 46 m². That gives a thrust of about 414 uN. The mass is about 1300 kg. Thus the acceleration from sunlight max is about 3.2 e-7 m/s². Of course, there are a lot of assumptions in that, the mass is probably higher, it won't be perfect reflectivity, and a good part of that time not all of it will be pointed in the correct direction, still, this is a fair estimate. The acceleration will also vary as one gets further from the Sun.

The units for A1 from Horizons are actually AU/day², and are subject to a very complex formula. That changes to 5.93321266 × 10^-8 m/s². It is even more complex than that, however, the actual acceleration depends on the distance from the Sun. Lucky for us, the numbers I calculated assume 1 AU, and at that point they are nearly identical. So that is a reasonable approximation, and this value is perfectly consistent with a low reflective pointing mostly away from the Sun Starman.

share|improve this answer

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  46 m^2, not m^s.
  $endgroup$
  – Skyler
  6 hours ago
  

  
  
  
  

add a comment | 

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13

$begingroup$

Sunlight pressure. The acceleration is 9.08 μN / m² (Assuming perfect reflectivity). The size is about 3.66* 12.6 = 46 m². That gives a thrust of about 414 uN. The mass is about 1300 kg. Thus the acceleration from sunlight max is about 3.2 e-7 m/s². Of course, there are a lot of assumptions in that, the mass is probably higher, it won't be perfect reflectivity, and a good part of that time not all of it will be pointed in the correct direction, still, this is a fair estimate. The acceleration will also vary as one gets further from the Sun.

The units for A1 from Horizons are actually AU/day², and are subject to a very complex formula. That changes to 5.93321266 × 10^-8 m/s². It is even more complex than that, however, the actual acceleration depends on the distance from the Sun. Lucky for us, the numbers I calculated assume 1 AU, and at that point they are nearly identical. So that is a reasonable approximation, and this value is perfectly consistent with a low reflective pointing mostly away from the Sun Starman.

share|improve this answer

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  46 m^2, not m^s.
  $endgroup$
  – Skyler
  6 hours ago
  

  
  
  
  

add a comment | 

13

$begingroup$

Sunlight pressure. The acceleration is 9.08 μN / m² (Assuming perfect reflectivity). The size is about 3.66* 12.6 = 46 m². That gives a thrust of about 414 uN. The mass is about 1300 kg. Thus the acceleration from sunlight max is about 3.2 e-7 m/s². Of course, there are a lot of assumptions in that, the mass is probably higher, it won't be perfect reflectivity, and a good part of that time not all of it will be pointed in the correct direction, still, this is a fair estimate. The acceleration will also vary as one gets further from the Sun.

The units for A1 from Horizons are actually AU/day², and are subject to a very complex formula. That changes to 5.93321266 × 10^-8 m/s². It is even more complex than that, however, the actual acceleration depends on the distance from the Sun. Lucky for us, the numbers I calculated assume 1 AU, and at that point they are nearly identical. So that is a reasonable approximation, and this value is perfectly consistent with a low reflective pointing mostly away from the Sun Starman.

share|improve this answer

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  46 m^2, not m^s.
  $endgroup$
  – Skyler
  6 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

Sunlight pressure. The acceleration is 9.08 μN / m² (Assuming perfect reflectivity). The size is about 3.66* 12.6 = 46 m². That gives a thrust of about 414 uN. The mass is about 1300 kg. Thus the acceleration from sunlight max is about 3.2 e-7 m/s². Of course, there are a lot of assumptions in that, the mass is probably higher, it won't be perfect reflectivity, and a good part of that time not all of it will be pointed in the correct direction, still, this is a fair estimate. The acceleration will also vary as one gets further from the Sun.

The units for A1 from Horizons are actually AU/day², and are subject to a very complex formula. That changes to 5.93321266 × 10^-8 m/s². It is even more complex than that, however, the actual acceleration depends on the distance from the Sun. Lucky for us, the numbers I calculated assume 1 AU, and at that point they are nearly identical. So that is a reasonable approximation, and this value is perfectly consistent with a low reflective pointing mostly away from the Sun Starman.

share|improve this answer

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

$endgroup$

share|improve this answer

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

edited 4 hours ago

Community♦

1

edited 4 hours ago

Community♦

1

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450

answered 9 hours ago

PearsonArtPhoto♦PearsonArtPhoto

82.7k16235450