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Problems with rounding giving too many digits
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$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
add a comment |
$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
Could round exactly and then useN:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
1 hour ago
add a comment |
$begingroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
$endgroup$
My current code is:
round = .1;
f[x_] := x + 4 - Sqrt[3 x^2 - 5]
xx = Solve[f[x] == 0, Reals];
StringForm["x=`1`",
If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round],
"none"]]
x=5.800000000000001`
which i want to give me an output of "x = 5.8" instead.
Any advice would be appreciated.
formatting round
formatting round
edited 46 mins ago
Alexey Popkov
38.5k4108263
38.5k4108263
asked 1 hour ago
WomblesWombles
584
584
$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
Could round exactly and then useN:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
1 hour ago
add a comment |
$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]
$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
Could round exactly and then useN:N[Round[Max[xx[[All, 1, 2]]], 1/10]]
$endgroup$
– Daniel Lichtblau
1 hour ago
$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
Could round exactly and then use
N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]$endgroup$
– Daniel Lichtblau
1 hour ago
$begingroup$
Could round exactly and then use
N: N[Round[Max[xx[[All, 1, 2]]], 1/10]]$endgroup$
– Daniel Lichtblau
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
You could add a StandardForm wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm in place of DecimalForm.
$endgroup$
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You could add a StandardForm wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
You could add a StandardForm wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
You could add a StandardForm wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
$endgroup$
You could add a StandardForm wrapper:
StringForm["x=`1`",StandardForm @ If[Length[xx]>=1,Round[Max[xx[[All,1,2]]],round],"none"]]
x=5.8
answered 1 hour ago
Carl WollCarl Woll
69.4k393179
69.4k393179
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
$begingroup$
Thank you! that worked and i have no idea why, i'll read the documentation for standardForm
$endgroup$
– Wombles
1 hour ago
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm in place of DecimalForm.
$endgroup$
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm in place of DecimalForm.
$endgroup$
add a comment |
$begingroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm in place of DecimalForm.
$endgroup$
StringForm["x=`1`", If[Length[xx] >= 1,
DecimalForm[Round[Max[xx[[All, 1, 2]]], round], DefaultPrintPrecision -> 2],
"none"]]
x = 5.8
Same result with NumberForm in place of DecimalForm.
edited 1 hour ago
answered 1 hour ago
kglrkglr
187k10203421
187k10203421
add a comment |
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
add a comment |
$begingroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
$endgroup$
StringJoin["x=",If[Length[xx] >= 1, ToString[Round[Max[xx[[All, 1, 2]]]*10]/10.]]
x = 5.8
answered 1 hour ago
mjwmjw
5228
5228
add a comment |
add a comment |
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$begingroup$
StringForm["x=1", If[Length[xx] >= 1, Round[Max[xx[[All, 1, 2]]], round // Rationalize] // N, "none"]]$endgroup$
– Bob Hanlon
1 hour ago
$begingroup$
Could round exactly and then use
N:N[Round[Max[xx[[All, 1, 2]]], 1/10]]$endgroup$
– Daniel Lichtblau
1 hour ago