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Hide python error message when ending ansible playbook with CTRL+C
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Whenever I terminate an ansible playbook using ctrl+c, it shows the following python error message, both on macOS and Ubuntu:
^CProcess WorkerProcess-22:
Traceback (most recent call last):
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/multiprocessing/process.py", line 297, in _bootstrap
self.run()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/process/worker.py", line 118, in run
self._final_q
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 140, in run
res = self._execute()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 612, in _execute
result = self._handler.run(task_vars=variables)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/shell.py", line 27, in run
result = command_action.run(task_vars=task_vars)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/command.py", line 24, in run
results = merge_hash(results, self._execute_module(task_vars=task_vars, wrap_async=wrap_async))
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 840, in _execute_module
res = self._low_level_execute_command(cmd, sudoable=sudoable, in_data=in_data)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 959, in _low_level_execute_command
rc, stdout, stderr = self._connection.exec_command(cmd, in_data=in_data, sudoable=sudoable)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/connection/local.py", line 133, in exec_command
stdout, stderr = p.communicate(in_data)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 939, in communicate
stdout, stderr = self._communicate(input, endtime, timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 1681, in _communicate
ready = selector.select(timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/selectors.py", line 415, in select
fd_event_list = self._selector.poll(timeout)
KeyboardInterrupt
Is there a way I could hide this? I am writing a cli-based application to be used on mac, Ubuntu, and Windows, and I need to hide this error log, but can't seem to find a way, neither in ansible nor in Python.
python ansible
asked 9 mins ago
sadmanshsadmansh
101
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sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Whenever I terminate an ansible playbook using ctrl+c, it shows the following python error message, both on macOS and Ubuntu:
^CProcess WorkerProcess-22:
Traceback (most recent call last):
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/multiprocessing/process.py", line 297, in _bootstrap
self.run()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/process/worker.py", line 118, in run
self._final_q
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 140, in run
res = self._execute()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 612, in _execute
result = self._handler.run(task_vars=variables)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/shell.py", line 27, in run
result = command_action.run(task_vars=task_vars)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/command.py", line 24, in run
results = merge_hash(results, self._execute_module(task_vars=task_vars, wrap_async=wrap_async))
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 840, in _execute_module
res = self._low_level_execute_command(cmd, sudoable=sudoable, in_data=in_data)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 959, in _low_level_execute_command
rc, stdout, stderr = self._connection.exec_command(cmd, in_data=in_data, sudoable=sudoable)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/connection/local.py", line 133, in exec_command
stdout, stderr = p.communicate(in_data)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 939, in communicate
stdout, stderr = self._communicate(input, endtime, timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 1681, in _communicate
ready = selector.select(timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/selectors.py", line 415, in select
fd_event_list = self._selector.poll(timeout)
KeyboardInterrupt
Is there a way I could hide this? I am writing a cli-based application to be used on mac, Ubuntu, and Windows, and I need to hide this error log, but can't seem to find a way, neither in ansible nor in Python.
python ansible
asked 9 mins ago
sadmanshsadmansh
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
Whenever I terminate an ansible playbook using ctrl+c, it shows the following python error message, both on macOS and Ubuntu:
^CProcess WorkerProcess-22:
Traceback (most recent call last):
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/multiprocessing/process.py", line 297, in _bootstrap
self.run()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/process/worker.py", line 118, in run
self._final_q
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 140, in run
res = self._execute()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 612, in _execute
result = self._handler.run(task_vars=variables)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/shell.py", line 27, in run
result = command_action.run(task_vars=task_vars)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/command.py", line 24, in run
results = merge_hash(results, self._execute_module(task_vars=task_vars, wrap_async=wrap_async))
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 840, in _execute_module
res = self._low_level_execute_command(cmd, sudoable=sudoable, in_data=in_data)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 959, in _low_level_execute_command
rc, stdout, stderr = self._connection.exec_command(cmd, in_data=in_data, sudoable=sudoable)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/connection/local.py", line 133, in exec_command
stdout, stderr = p.communicate(in_data)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 939, in communicate
stdout, stderr = self._communicate(input, endtime, timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 1681, in _communicate
ready = selector.select(timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/selectors.py", line 415, in select
fd_event_list = self._selector.poll(timeout)
KeyboardInterrupt
Is there a way I could hide this? I am writing a cli-based application to be used on mac, Ubuntu, and Windows, and I need to hide this error log, but can't seem to find a way, neither in ansible nor in Python.
python ansible
asked 9 mins ago
sadmanshsadmansh
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Whenever I terminate an ansible playbook using ctrl+c, it shows the following python error message, both on macOS and Ubuntu:
^CProcess WorkerProcess-22:
Traceback (most recent call last):
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/multiprocessing/process.py", line 297, in _bootstrap
self.run()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/process/worker.py", line 118, in run
self._final_q
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 140, in run
res = self._execute()
File "/usr/local/lib/python3.7/site-packages/ansible/executor/task_executor.py", line 612, in _execute
result = self._handler.run(task_vars=variables)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/shell.py", line 27, in run
result = command_action.run(task_vars=task_vars)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/command.py", line 24, in run
results = merge_hash(results, self._execute_module(task_vars=task_vars, wrap_async=wrap_async))
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 840, in _execute_module
res = self._low_level_execute_command(cmd, sudoable=sudoable, in_data=in_data)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/action/__init__.py", line 959, in _low_level_execute_command
rc, stdout, stderr = self._connection.exec_command(cmd, in_data=in_data, sudoable=sudoable)
File "/usr/local/lib/python3.7/site-packages/ansible/plugins/connection/local.py", line 133, in exec_command
stdout, stderr = p.communicate(in_data)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 939, in communicate
stdout, stderr = self._communicate(input, endtime, timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/subprocess.py", line 1681, in _communicate
ready = selector.select(timeout)
File "/usr/local/Cellar/python/3.7.3/Frameworks/Python.framework/Versions/3.7/lib/python3.7/selectors.py", line 415, in select
fd_event_list = self._selector.poll(timeout)
KeyboardInterrupt
Is there a way I could hide this? I am writing a cli-based application to be used on mac, Ubuntu, and Windows, and I need to hide this error log, but can't seem to find a way, neither in ansible nor in Python.
python ansible
python ansible
asked 9 mins ago
sadmanshsadmansh
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
sadmanshsadmansh
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
sadmanshsadmansh
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 9 mins ago
sadmanshsadmansh
101
asked 9 mins ago
sadmanshsadmansh
101
101
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
sadmansh is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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