Ryfujk

How to mitigate "bandwagon attacking" from players?

How Should I Define/Declare String Constants

What can I substitute for soda pop in a sweet pork recipe?

Finding the number of integers that are a square and a cube at the same time

How to satisfy a player character's curiosity about another player character?

Do commercial flights continue with an engine out?

How do Japanese speakers determine the implied topic when none has been mentioned?

Does Windows 10's telemetry include sending *.doc files if Word crashed?

Removing debris from PCB

Why is my solution for the partial pressures of two different gases incorrect?

How to add multiple differently colored borders around a node?

Why zero tolerance on nudity in space?

How to approximate rolls for potions of healing using only d6's?

What is the wife of a henpecked husband called?

How to use a mathematical expression as xticklable

Predict mars robot position

If all harmonics are generated by plucking, how does a guitar string produce a pure frequency sound?

When does coming up with an idea constitute sufficient contribution for authorship?

Prove that every even perfect number is a triangular number.

Find the number of ways to express 1050 as sum of consecutive integers

Metadata API deployments are failing in Spring '19

I am on the US no-fly list. What can I do in order to be allowed on flights which go through US airspace?

Why can I easily sing or whistle a tune I've just heard, but not as easily reproduce it on an instrument?

Naming things the POV character doesn't know

Obtaining a matrix of complex values from associations giving the real and imaginary parts of each element?

Eigenvalues of matrix not giving imaginary partsPlot values of an $mtimes n$ matrix on the complex plane with color varying along $m$Real and Imaginary matrixDefining a non-standard algebraic numberFind the parameter values for my matrix for it to have imaginary eigenvaluesEfficiently select the smallest magnitude element from each column of a matrixGenerate random matrix where the entries in each column are drawn from a different rangeSample matrix indices in proportion to the matrix element valuesKeyed eigensystem for nested AssociationConverting a list of associations into a single association

5

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

$endgroup$

add a comment | 

5

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

$endgroup$

add a comment | 

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

$endgroup$

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

testmatrix = Join[Values[matrix], 2]`

share|improve this question

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

share|improve this question

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

edited 7 hours ago

MarcoB

36.6k556112

edited 7 hours ago

MarcoB

36.6k556112

asked 14 hours ago

MKFMKF

1588

asked 14 hours ago

MKFMKF

1588

2 Answers
2

active

oldest

votes

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 9 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 7 hours ago

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192530%2fobtaining-a-matrix-of-complex-values-from-associations-giving-the-real-and-imagi%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 9 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 9 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  7 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 9 hours ago

kglrkglr

186k10203422

$endgroup$

Apply[Complex, matrix, {2}]

share|improve this answer

answered 9 hours ago

kglrkglr

186k10203422

answered 9 hours ago

kglrkglr

186k10203422

answered 9 hours ago

kglrkglr

186k10203422

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 7 hours ago

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 7 hours ago

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  6 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 7 hours ago

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 7 hours ago

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

answered 14 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154